Albarellak

2021-01-08

Find the following probabilities for the standard normal distribution $Pr(z>2.5)$

joshyoung05M

Skilled2021-01-09Added 97 answers

$z=\frac{x-\mu}{\sigma}$

The normal distribution is symmetric about mean 0.5.

$P(z>2.5)=0.5-Pr(z\le 2.5)$

The probability that the z lies between 0 and 2.5 is equal to the area that lies under the curve from 0 and 2.5.

In the column headed by A across 2.5 the corresponding value is 0.4938.

The probability $P(0\le z\le 2.5)$ is ${A}_{2.5}$.

So the value of ${A}_{2.5}$ from the appendix C is 0.4938.

The value of $P(z>2.5)$

$P(z>2.5)=0.5\u20140.4938=0.0062$

Aswer is 0.0062.

Read carefully and choose only one option

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