Different students groups in a class of the Department of Chemistry were conducting lab experiments to determine changes in number of moles of chemical-A due to addition of different samples of chemical-B. They got the following results: 9.7,3.4,7.4,3.9,5.2,6.7,3.9,3.3,9.8,2.9,6.2,9.6 Calculate the sample variance value of the data. Note: The answer must be written using two decimal places. Answer: ? Different students groups in a class of the Department of Chemistry were conducting lab experiments to determine changes in number of moles of chemical-A due to addition of different samples of chemical-B. They got the following results: 3.8,2.7,2,3.5,2,10,1.4,4.9,3.5,3.5,1.4,5.3,4.6,6.7,6.8,2.9,3.8,4.6 Calculate the sample range of the data. Note: The answer must be written using two decimal places. Answer: ?

Question

Different students groups in a class of the Department of Chemistry were conducting lab experiments to determine changes in number of moles of chemical-A due to addition of different samples of chemical-B. They got the following results:  9.7,3.4,7.4,3.9,5.2,6.7,3.9,3.3,9.8,2.9,6.2,9.6  Calculate the sample variance value of the data.  Note: The answer must be written using two decimal places.  Answer: ?  Different students groups in a class of the Department of Chemistry were conducting lab experiments to determine changes in number of moles of chemical-A due to addition of different samples of chemical-B. They got the following results:  3.8,2.7,2,3.5,2,10,1.4,4.9,3.5,3.5,1.4,5.3,4.6,6.7,6.8,2.9,3.8,4.6  Calculate the sample range of the data.  Note: The answer must be written using two decimal places.  Answer: ?

Ancessitere · Accepted Answer

Step 1 Given data is 9.7,3.4,7.4,3.9,5.2,6.7,3.9,3.3,9.8,2.9,6.2,9.6 Sample size (n)=12 Sample mean x―=9.7+3.4+⋯9.612 x―=7212 x―=6 Step 2 Sample variance (s2)=∑i(xi−x―)2n−1 s2=(9.7−6)2+(3.4−6)2+⋯+(9.6−6)212−1 s2=6.97 Step 3 Given, 3.8,2.7,2,3.5,2,10,1.4,4.9,3.5,3.5,1.4,5.3,4.6,6.7,6.8,2.9,3.8,4.6 Sample range=Maximum−Minimum Sample range=10−1.4 Sample range=8.60

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