generals336

2021-01-31

The centers for Disease Control reported the percentage of people 18 years of age and older who smoke (CDC website, December 14, 2014). Suppose that a study designed to collect new data on smokers and Questions Navigation Menu preliminary estimate of the proportion who smoke of .26.

a) How large a sample should be taken to estimate the proportion of smokers in the population with a margin of error of .02?(to the nearest whole number) Use 95% confidence.

b) Assume that the study uses your sample size recommendation in part (a) and finds 520 smokers. What is the point estimate of the proportion of smokers in the population (to 4 decimals)?

c) What is the 95% confidence interval for the proportion of smokers in the population?(to 4 decimals)?

a) How large a sample should be taken to estimate the proportion of smokers in the population with a margin of error of .02?(to the nearest whole number) Use 95% confidence.

b) Assume that the study uses your sample size recommendation in part (a) and finds 520 smokers. What is the point estimate of the proportion of smokers in the population (to 4 decimals)?

c) What is the 95% confidence interval for the proportion of smokers in the population?(to 4 decimals)?

avortarF

Skilled2021-02-01Added 113 answers

Step 1

Given:

Error margin (E) equals 0.02

Level of confidence: 95%

Population proportion (p) = 0.26

Step 2

(a)

The following formula could be used to determine the sample size:

$n=p(1-p){\left(\frac{{Z}_{\frac{\alpha}{2}}}{E}\right)}^{2}$

Step 3

You may compute the sample size at a 95% confidence level as follows:

The value of $\frac{{Z}_{\alpha}}{2}$ The number 1.96 corresponds to a 95% confidence level.

$n=p(1-p){\left(\frac{{Z}_{\frac{\alpha}{2}}}{E}\right)}^{2}$

$=0.26(1-0.26){\left(\frac{1.96}{0.02}\right)}^{2}$

$=0.1924\times 9604$

=1847.810

$\approx 1848$

Step 4

(b)

Here, X = 520 and n = 1848.

One method for calculating the point estimate is:

$\hat{p}=\frac{X}{n}$

$=\frac{520}{1848}$

=0.2814

Step 5

(c)

The following formula can be used to determine the population's smoking prevalence and its 95% confidence interval:

$CI=\hat{p}\pm {Z}_{\frac{\alpha}{2}}\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$

$=0.2814\pm 1.96\times \sqrt{\frac{0.2814(1-0.2814)}{1848}}$

$=0.2814\pm 0.0205$

=(0.2609,0.3019)

Construct all random samples consisting three observations from the given data. Arrange the observations in ascending order without replacement and repetition.

86 89 92 95 98.Read carefully and choose only one option

A statistic is an unbiased estimator of a parameter when (a) the statistic is calculated from a random sample. (b) in a single sample, the value of the statistic is equal to the value of the parameter. (c) in many samples, the values of the statistic are very close to the value of the parameter. (d) in many samples, the values of the statistic are centered at the value of the parameter. (e) in many samples, the distribution of the statistic has a shape that is approximately NormalFind the mean of the following data: 12,10,15,10,16,12,10,15,15,13.

The equation has a positive slope and a negativey-intercept.

1) y=−2x−3

2) y=2−3x

3) y=2+3x

4) y=−2+3xWhat term refers to the standard deviation of the sampling distribution?

Fill in the blanks to make the statement true: $30\%of\u20b9360=\_\_\_\_\_\_\_\_$.

What percent of $240$ is $30$$?$

The first 15 digits of pi are as follows: 3.14159265358979

The frequency distribution table for the digits is as follows:

$\begin{array}{|cc|}\hline DIGIT& FREQUENCY\\ 1& 2\\ 2& 1\\ 3& 2\\ 4& 1\\ 5& 3\\ 6& 1\\ 7& 1\\ 8& 1\\ 9& 3\\ \hline\end{array}$

Which two digits appear for 3 times each?

A) 1, 7

B) 2, 6

C) 5, 9<br<D) 3, 8How to write

as a percent?$\frac{2}{20}$ What is the simple interest of a loan for $1000 with 5 percent interest after 3 years?

What number is 12% of 45?

The probability that an automobile being filled with gasoline also needs an oil change is 0.30; the probability that it needs a new oil filter is 0.40; and the probability that both the oil and the filter need changing is 0.10. (a) If the oil has to be changed, what is the probability that a new oil filter is needed? (b) If a new oil filter is needed, what is the probability that the oil has to be changed?

Leasing a car. The price of the car is$45,000. You have $3000 for a down payment. The term of the lease is and the interest rate is 3.5% APR. The buyout on the lease is51% of its purchase price and it is due at the end of the term. What are the monthly lease payments (before tax)?

The mean of sample A is significantly different than the mean of sample B. Sample A: $59,33,74,62,87,73$ Sample B: $53,67,72,57,93,79$ Use a two-tailed $t$-test of independent samples for the above hypothesis and data. What is the $p$-value?

What is mean and its advantages?