The original function is given, y = 2 x 2 </msup> + 2 x + 7 at the

gnatopoditw

gnatopoditw

Answered question

2022-06-19

The original function is given,
y = 2 x 2 + 2 x + 7
at the point ( 4 , 47 ).
I found the tangent line from the original function which is:
f ( x ) = 4 x + 2.
The question states that the tangent line can be written as y = m x + b and asks me to find the slope ( m) as well as the y-intercept ( b).
I have found the slope which is 18, by plugging in the x-value from the point ( 4 , 47 ) into the tangent line: so I have f ( x ) = 4 x + 2 which equals 4 ( 4 ) + 2 which is 18.
The way I'm trying to find the y-intercept is by doing: y 47 = 18 ( x 3 ) which is 7, but it's wrong the answer is 25.
What mistake am I making that's leading me to get 7?

Answer & Explanation

kpgt1z

kpgt1z

Beginner2022-06-20Added 23 answers

Instead of y 47 = 18 ( x 3 ), you should say y 47 = 18 ( x 4 ), because the point ( 4 , 47 ) is on the tangent line, and then you'll get the correct answer.
enrotlavaec

enrotlavaec

Beginner2022-06-21Added 3 answers

You're making a mistake at this part :
x 3
it should be
x 4
You can also use y = m x + c instead of the complicated y y 1 = m ( x x 1 ). Because you already know m and a point ( 4 , 47 ) then you just need to find c, that way is gonna be easier and will make you avoid calculation mistake

Do you have a similar question?

Recalculate according to your conditions!

New Questions in High school statistics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?