Finding a basis of an infinite-dimensional vector space? the opposite day, my trainer become speakme limitless-dimensional vector spaces and headaches that arise when trying to find a foundation for the ones. He referred to that it is been demonstrated that a few (or all, do no longer pretty remember) infinite-dimensional vector areas have a foundation (the end result uses an Axiom of choice, if I recall efficiently), that is, an endless listing of linearly independent vectors, such that any detail within the area can be written as a finite linear aggregate of them. however, my instructor stated that honestly finding one is simply complicated, and i were given a experience that it changed into essentially not possible, which jogged my memory of Banach-Tarski paradox, where it is technical

taumulurtulkyoy

taumulurtulkyoy

Answered question

2022-10-17

Finding a basis of an infinite-dimensional vector space?
the opposite day, my trainer become speakme limitless-dimensional vector spaces and headaches that arise when trying to find a foundation for the ones. He referred to that it is been demonstrated that a few (or all, do no longer pretty remember) infinite-dimensional vector areas have a foundation (the end result uses an Axiom of choice, if I recall efficiently), that is, an endless listing of linearly independent vectors, such that any detail within the area can be written as a finite linear aggregate of them. however, my instructor stated that honestly finding one is simply complicated, and i were given a experience that it changed into essentially not possible, which jogged my memory of Banach-Tarski paradox, where it is technically 'viable' to decompose the sector in a given paradoxical way, however this can not be truly exhibited. So my question is, is the basis state of affairs analogous to that, or is it surely viable to explicitly discover a basis for endless-dimensional vector areas?

Answer & Explanation

latatuy

latatuy

Beginner2022-10-18Added 12 answers

It's known that the statement that every vector space has a basis is equivalent to the axiom of choice, which is independent of the other axioms of set theory. This is generally taken to mean that it is in some sense impossible to write down an "explicit" basis of an arbitrary infinite-dimensional vector space. On the other hand,
Some infinite-dimensional vector spaces do have easily describable bases; for example, we are often interested in the subspace spanned by a countable sequence v 1 , v 2 , . . . of linearly independent vectors in some vector space V, and this subspace has basis { v 1 , v 2 , . . . } by design.
For many infinite-dimensional vector spaces of interest we don't care about describing a basis anyway; they often come with a topology and we can therefore get a lot out of studying dense subspaces, some of which, again, have easily describable bases. In Hilbert spaces, for example, we care more about orthonormal bases (which are not Hamel bases in the infinite-dimensional case); these span dense subspaces in a particularly nice way.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in High school statistics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?