What is the projection of <6,5,3> onto <2,-1,8>?

miljanwpd2

miljanwpd2

Answered question

2023-03-23

What is the projection of < 6 , 5 , 3 > onto < 2 , - 1 , 8 > ?

Answer & Explanation

Saottah87e

Saottah87e

Beginner2023-03-24Added 6 answers

Given a = < 6 , 5 , 3 > and b = < 2 , - 1 , 8 > , we can find p r o j b a , the vector projection of a onto b using the following formula:
p r o j b a = ( a b | b | ) b | b |
That is, the dot product of the two vectors divided by the magnitude of b , multiplied by b divided by its magnitude. The second quantity is a vector quantity, as we divide a vector by a scalar. Note that we divide b by its magnitude in order to obtain a unit vector (vector with magnitude of 1 ). You may have noticed that the first quantity is a scalar because we know that the dot product of two vectors always yields a scalar value.
Therefore, the scalar projection of a onto b is c o m p b a = a b | b | , also written | p r o j b a |
Taking the dot product of the two vectors will be our first step.
a b = < 6 , 5 , 3 > < 2 , - 1 , 8 >
( 6 2 ) + ( 5 - 1 ) + ( 3 8 )
12 - 5 + 24 = 31
Then, by taking the square root of the sum of the squares of each component, we can determine the size of b
| b | = ( b x ) 2 + ( b y ) 2 + ( b z ) 2
| b | = ( 2 ) 2 + ( - 1 ) 2 + ( 8 ) 2
4 + 1 + 64 = 69
And now we have everything we need to find the vector projection of a onto b
p r o j b a = 31 69 < 2 , - 1 , 8 > 69
31 < 2 , - 1 , 8 > 69
= 31 69 < 2 , - 1 , 8 >
The coefficient can be distributed to each element of the vector and written as follows:
< 62 69 , - 31 69 , 248 69 >
The scalar projection of a onto b is just the first half of the formula, where c o m p b a = a b | b | . Therefore, the scalar projection is 31 69 , which does not simplify any further, besides to rationalize the denominator if desired, giving 31 69 69

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