Recent questions in Balmer Series

Atomic PhysicsAnswered question

Iyana Macdonald 2022-05-15

From the figure find the shortest wavelength present in the Balmer series of hydrogen, If $R=1.097\times {10}^{7}\text{}{m}^{-1}$

Atomic PhysicsAnswered question

Sappeycuii 2022-05-14

Energy vs wavelength relation is given by, $E(eV)=\frac{1241}{nm}$. Energy of H-atom in the ground state is -13.6eV as form the relation $E(eV)=-13.6\frac{{Z}_{eff}^{2}}{{n}^{2}}(eV)$. Find that in which transition on hydrogen atom is the wavelength 486.1 nm produced? To which seriesdoes it belong ?

Atomic PhysicsAnswered question

Annabel Sullivan 2022-05-14

What is the smallest-wavelength line in the Balmer series? Is it in the visible part of the spectrum?

Atomic PhysicsAnswered question

Waylon Mcbride 2022-05-13

For the hydrogen atom, the Balmer Series is the series of line spectra produced when an election falls from any higher energy level and has n=2 as its final energy state. The longest wavelength is the Balmer Series is 656.7 nm. what was the initial principal energy level (n) associated with this photon.

Will the energy value in the trasnistion be the geatest or smalles in the entie Balmer Series?

Will the energy value in the trasnistion be the geatest or smalles in the entie Balmer Series?

Atomic PhysicsAnswered question

Leon Robinson 2022-05-13

Calculate the longest wavelength of the hydrogen Balmer series using the Bohr model of the atom.

Atomic PhysicsAnswered question

quorums15lep 2022-05-10

The first member of Balmer series of hydrogen atom has a wavelength of 6561 Å. Find wavelength of the second member of the Balmer series (in nm)

Atomic PhysicsAnswered question

garcialdaria2zky1 2022-05-09

Calculate the two longest wavelength of the Balmer series of triply ionized berillium (Z=4)

Atomic PhysicsAnswered question

Amappyaccon22j7e 2022-05-08

Which has a larger frequency the 4th line of Balmer series or the 4th line of the Lyman series ?

Provide an explanation

Provide an explanation

Atomic PhysicsAnswered question

Flakqfqbq 2022-05-08

What electron transitions account for the Balmer series?

Atomic PhysicsAnswered question

Davin Sheppard 2022-05-03

For the hydrogen atom, the Balmer Series is the series of line spectra produced when an election falls from any higher energy level and has n=2 as its final energy state. The longest wavelength is the Balmer Series is 656.7 nm. what was the initial principal energy level (n) associated with this photon

Atomic PhysicsAnswered question

esbagoar7kh 2022-05-02

What is smallest wavelength line in the Balmer series:

A) 364.5 nm

B) 402.5 nm

C) 388 nm

D) 656 nm

A) 364.5 nm

B) 402.5 nm

C) 388 nm

D) 656 nm

Atomic PhysicsAnswered question

airesex2 2022-05-02

Calculate the wave number for the second line of the Palmer series

Atomic PhysicsAnswered question

Edith Mayer 2022-04-12

Calculate the wavelength and predict the color of the first two lines of the Balmer series for hydrogen. Use the table below.

Wavelength of emission (nm) - Color

400-450 - Violet

450-490 - Blue

490-550 - Green

550-580 - Yellow

580-650 - Orange

650-700 - Red

Wavelength of emission (nm) - Color

400-450 - Violet

450-490 - Blue

490-550 - Green

550-580 - Yellow

580-650 - Orange

650-700 - Red

Atomic PhysicsAnswered question

Jaeden Weaver 2022-04-12

What is wavelength in the Balmer series of hydrogen corresponding to the transition fron n=4 to n=2

- 1
- 2

To understand the Balmer Series, you need to understand the energy levels of hydrogen atoms and how they relate to the frequency of light emitted from the atom. The Balmer Series Formula is a simple equation that allows us to calculate these energy levels and understand the behavior of atoms. This equation has been used to answer many questions about the nature of matter and the behavior of stars, and it can be seen in the absorption and emission spectra of hydrogen atoms. To answer questions about the Balmer Series, it is important to understand the equations and how they are related to the energy levels of hydrogen atoms. By understanding this equation, we can gain a better understanding of the behavior of atoms and the universe around us.