How to find the polynomial function whose graph passes through (2,4), (3,6), (5,10)?

doctorfinger1ci

doctorfinger1ci

Answered question

2022-12-27

How to find the polynomial function whose graph passes through (2,4), (3,6), (5,10)?

Answer & Explanation

milanduy19

milanduy19

Beginner2022-12-28Added 8 answers

Simplest solution:
f(x)=2x
General solution:
f(x)=P(x)(x310x2+31x30)+2x
Given solution: Given:
(2,4), (3,6), (5,10)
Note that each y coordinate is twice the corresponding x coordinate.
So a suitable polynomial function is:
f(x)=2x
But keep in mind that there are other polynomial functions that pass through these three points.
We can add any multiple (scalar or polynomial) of a cubic whose zeros lie at those three points, namely:
(x2)(x3)(x5)=x310x2+31x30
Therefore the most general solution is:
f(x)=P(x)(x310x2+31x30)+2x
for any polynomial P(x).

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