Find the smallest number which when divided by 28 and 32, respectively, leaves a remainder, 8 and 12 respectively.

animeagan0o8

animeagan0o8

Answered question

2023-01-22

Find the smallest number which when divided by 28 and 32, respectively, leaves a remainder, 8 and 12 respectively.

Answer & Explanation

Jacquelyn Watts

Jacquelyn Watts

Beginner2023-01-23Added 12 answers

28-8=20 and 32-`12=20 are divisible by the required numbers.
Prime factors of 28 are
28=2×2×7
Prime factors of 32 are
32=2×2×2×2
LCM of 28 and 32 is
LCM28,32=2×2×2×2×7=224
The required the smallest number =224-20=204

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?