The equation of the line with slope -(3)/(2) and which is concurrent with the lines 4x+3y−7=0 and 8x+5y−1=0 is A)3x+2y−63=0; B)3x+2y−2=0; C)2y−3x−2=0; D)none of these

inimigurhkg

inimigurhkg

Answered question

2023-02-16

The equation of the line with slope 3 2 and which is concurrent with the lines 4x+3y−7=0 and 8x+5y−1=0 is
A)3x+2y−63=0;
B)3x+2y−2=0;
C)2y−3x−2=0;
D)none of these

Answer & Explanation

Brisa Fitzgerald

Brisa Fitzgerald

Beginner2023-02-17Added 5 answers

The correct answer is C
3x+2y−2=0

We have :
4x+3y−7=0 ...(1)
8x+5y=0 ...(2)
The equation of the line with slope −\frac{3}{2} is given below :
y = 3 2 x + c 3 2 x + y c = 0 . . . ( 3 )
The lines (1), (2) and (3) are concurrent.
| 4 3 7 8 5 1 3 2 1 c | = 0 4 ( 5 c + 1 ) 3 ( 8 c + 3 2 ) 7 ( 8 15 2 ) = 0 20 c + 4 + 24 c 9 2 56 + 105 2 = 0 40 c + 8 + 48 c 9 112 + 105 2 = 0 8 c = 8 c = 1
On substituting c=1 in y = 3 2 x + c, we get:
y = 3 2 x + 1 3 x + 2 y 2 = 0

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?