What are the illegal values of b in the fraction (2b^2+3b-10)/(b^2-2b-8)?

juanikitoexgv5y

juanikitoexgv5y

Answered question

2023-03-24

What are the illegal values of #b# in the fraction 2 b 2 + 3 b - 10 b 2 - 2 b - 8 ?

Answer & Explanation

nickalasaurus6ea0

nickalasaurus6ea0

Beginner2023-03-25Added 5 answers

2 b 2 + 3 b - 10 b 2 - 2 b - 8 is undefined if ( b 2 - 2 b - 8 ) = 0
Calculating:
XXX b 2 - 2 b - 8 = ( x - 4 ) ( x + 2 )
which suggests that the initial expression is undefifable if x - 4 = 0 or x + 2 = 0
So result is: x=4 or x=-2

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