Expert answers to "To solve: The equation x2−2.450x−1.500=0 using quadratic formula..."

foass77W

Answered question

2021-05-22

To solve:
The equation

x^{2} - 2.450 x - 1.500 = 0

using quadratic formula and a calculator, rounding to three decimals.

Answer & Explanation

Lacey-May Snyder

Skilled2021-05-23Added 88 answers

Step 1
Quadratic Formula: For a quadratic equation $a x^{2} + b x + c = 0,$ where $a \neq 0$ ,
the slutions are $x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
Step 2
Given: $x^{2} - 2.450 x + 1.500 = 0$
Here, $a = 1, b = - 2.450$ and $c = 1.500$
Substitute these values in quadratic formula.
$x = \frac{- (- 2.450) \pm \sqrt{(- 2.450)^{2} - 4 (1) (1.500)}}{2 (1)}$
$= \frac{2.450 \pm \sqrt{6.0025 - 6}}{2}$
Let us find the values of x using calculator.
$x = \frac{2.450 + \sqrt{0.0025}}{2} = \frac{2.5}{2} = 1.25$
$x = \frac{2.450 - \sqrt{0.0025}}{2} = \frac{2.4}{2} = 1.2$
Rounding to three decimals, the solutions are $x = 1.200, x = 1.250 .$

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