 sanuluy

2020-11-05

Test the claim that the proportion of people who own cats is significantly different than $50\mathrm{%}$ at the 0.01 significance level.
Based on a sample of 300 people, $41\mathrm{%}$ owned cats
Hint: Multiply to obtain the number of successes

The test statistic is: ? (to 2 decimals)
The p-value is: ? (to 4 decimals) rogreenhoxa8

The number of success will be:

$x=123$
It is necessary to test the following alternative and null hypotheses:

The z-statistic is computed as follows:

The required P-value can be obtained by using the standard normal table. For this case, first, find the area under the standard normal curve to the left of the z score of -3.12 (approx to two decimal places). The required area is 0 .000904. Now, this area should be doubled to reflect the nature of a two-tailed test that is 0.0018. Hence, the required P-value is 0.0018.
As the p-value 0.0018 is less than 0.01 level of signfiicance, the null hypothesis is rejected.
The test statistic is: -3.12(to 2 decimals)
The p-value is: 0.0018 (to 4 decimals)

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