The sum of four consecutive multiples of 6 is 84.

pancha3

pancha3

Answered question

2021-08-13

The sum of four consecutive multiples of 6 is 84. Find the four multiples?

Answer & Explanation

Mitchel Aguirre

Mitchel Aguirre

Skilled2021-08-14Added 94 answers

Step 1
let's suppose four multiples are =(n),(n+1),(n+2),(n+3).
than they are the multiple of 6 than =(6n),6(n+1),6(n+2),6(n+3).
than, according to question,
(6n)+6(n+1)+6(n+2)+6(n+3)=84
then 24n+36=84
24n=8436
24n=48
Hence, n=2
Step 2
6n=6×2=12
6(n+1)=6(2+1)=18
6(n+2)=6(2+2)=24
6(n+3)=6(2+3)=30
Checkout:
12+18+24+30=84
Result:
The four multiples of 6 are 12, 18, 24 and 30.

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