Let P(x, y) be a point on the graph ofy=x.Express the distance, d, from P to (2, 0) as a function of the point's x-coordinate.

d=(x–2)2+y2=(x−2)2+(x)2=x2–4x+4+x=x2–3x+4

Question: "Let P(x, y) be a point on the..."

tinfoQ

2021-08-09

Let P(x, y) be a point on the graph of

y = \sqrt{x} .

Express the distance, d, from P to (2, 0) as a function of the point's x-coordinate.

Nola Robson

Skilled2021-08-10Added 94 answers

$d = \sqrt{{(x - 2)}^{2} + y^{2}} = \sqrt{{(x - 2)}^{2} + {(\sqrt{x})}^{2}} = \sqrt{x^{2} - 4 x + 4 + x} = \sqrt{x^{2} - 3 x + 4}$

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