An electric utility company determines the monthly bill by charging 85.4 cents per kilowatt-hour (kWh) used plus a base charge of $17.55 per month. Thus, the monthly charge is given by the function f(W)=0.854W+17.55 dollars, where W is the number of kilowatt-hours. a. Find f (6000) and explain what it means. b. What is the monthly charge if 9500 kWh are used? a. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answers. Type integers or decimals.) A. f(6000)= nothing. The charge for 6000 kWh is $nothing. B. f(6000)= nothing. The charge for nothing kWh is $6000. b. The monthly charge is $nothing if 9500 kWh are used. (Simplify your answer. Type an integer or a decimal.)

Question

An electric utility company determines the monthly bill by charging 85.4 cents per​ kilowatt-hour (kWh) used plus a base charge of ​$17.55 per month.​ Thus, the monthly charge is given by the function f(W)=0.854W+17.55 ​dollars, where W is the number of​ kilowatt-hours.   a. Find f (6000​) and explain what it means.  b. What is the monthly charge if 9500 kWh are​ used?  a. Select the correct choice below and fill in the answer box to complete your choice.  ​(Simplify your answers. Type integers or​ decimals.)  A. ​f(6000​)= nothing.  The charge for 6000 kWh is $nothing.  B. ​f(6000​)= nothing.  The charge for nothing kWh is ​$6000.  b. The monthly charge is ​$nothing if 9500 kWh are used. ​ (Simplify your answer. Type an integer or a​ decimal.)

opsadnojD · Accepted Answer

Step 1  Given that  An electric utility company determines the monthly bill by charging 85.4 cents per​ kilowatt-hour (kWh) used plus a base charge of ​$17.55 per month.​ Thus, the monthly charge is given by the function f(W)=0.854W+17.55 ​dollars, where W is the number of​ kilowatt-hours.  Step 2  To find a. f(6000).  b. What is the monthly charge if 9500 kWh is used.  a. To find: f(6000).  The monthly charge is given by function, f(W)=0.854W+17.55  So to find f(6000) substitute W=6000∈f(W)=0.854W+17.55,  ⇒f(6000)=0.854(6000)+17.55  ⇒f(6000)=5141.55  Therefore there is monthly charge of $5141.55 if 6000 kWh is used.  Step 3   b. To find What is the monthly charge if 9500 kWh is used.   Substitute W=9500∈f(W)=0.854W+17.55,   f(9500)=0.854(9500)+17.55  ⇒f(9500)=8130.55   Therefore the monthly charge if 9500 kWh is used is $8130.55.

An electric utility company determines the monthly bill by charging 85.4 cents p

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