Let y=f(x) be a functD=(-12,\ 13) and range R=(-\infty,\ \infty).

Step 1
As we know:
Domain represent the set of inputs for a function.
Raange represent the set of outputs for a function.
When a function is transformed, its domain and/or range will change
If only inputs are transformed, then only the domain will change.If only the outputs are transformed, then only the range will change.If both the inputs and outputs are transformed, then both the domain and range will change.
For Example:
Let ${\displaystyle f\left(x\right)}$ is function with Domain ${\displaystyle =(a,b)}$ and Range ${\displaystyle =(c,d)}$
1) If ${\displaystyle f\left(x\right)\to f\left(mx\right)}$ than Domain ${\displaystyle =(a,b\to (a\times m,b\times m)}$ and Range will be unchanged that is Range ${\displaystyle =(c,d)}$
2) If ${\displaystyle f\left(x\right)\to f\left(\frac{x}{n}\right)}$ the Domain ${\displaystyle =(a,b)\to (\frac{a}{n},\frac{b}{n})}$ and Range will be unchanged that is Range ${\displaystyle =(c,d)}$
3) If ${\displaystyle f\left(x\right)\to mf\left(x\right)}$ than Domain ${\displaystyle =(a,b)}$ and Range ${\displaystyle =(c,d)\to (mc,md)}$
4) If ${\displaystyle f\left(x\right)\to f\left(x\right)\pm m}$ than Domain ${\displaystyle =(a,b)}$ and Range ${\displaystyle =(c,d)\to (c\pm m,d\pm m)}$
5) If ${\displaystyle f\left(x\right)\to mf\left(nx\right)thanDomain=(a,b)\to (na,nb)}$ and Range ${\displaystyle =(c,d)\to (mc,md)}$
6) If ${\displaystyle f\left(x\right)\to mf\left(nx\right)\pm p}$ than Domain ${\displaystyle =(a,b)\to (na,nb)}$ and Range ${\displaystyle =(c,d)\to (mc,md)\to (mc\pm p,md\pm p)}$
Step 2
a) ${\displaystyle y=f\left(\frac{1}{2}x\right)}$
Here,Only Inputs are transformed, then only domain will change.
${\displaystyle \Rightarrow }$ (inputs, outputs)
Since the outputs of this function are not being changed with the transformation ${\displaystyle y=f\left(\frac{1}{2}x\right)}$, that means the range is also not being changed.
So, The Range will remain ${\displaystyle R=(-\mathrm{\infty },\mathrm{\infty }).}$
Domain: ${\displaystyle (-12,13)\to (-\frac{12}{2},\frac{13}{2})=(-6,\frac{13}{2})}$
So,
Domain: ${\displaystyle (-6,\frac{13}{2})}$
Range: ${\displaystyle (-\mathrm{\infty },\mathrm{\infty })}$
Step 3
b) Given ${\displaystyle y=5f\left(2x\right)-2}$
Here
Both the inputs and outputs are transformed,then both domain and range will change
${\displaystyle \Rightarrow }$ (inputs, outputs)
Domain: