1) 4m3n34m−3n2 2) 3mn44m0 3) 3u−23u−1v0 4) −a−6b−5{−2b2⋅(a3b−3)6}

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1) 4m3n34m−3n2  2) 3mn44m0  3) 3u−23u−1v0  4) −a−6b−5{−2b2⋅(a3b−3)6}

Nicole Conner · Accepted Answer

In algebra, to use numerals, symbols, and letters called variables, or pro-numerals, and combinations of both. They stand for the unknown values. Algebraic expressions or equations, the unknown values are represented by pro-numerals or variables. The variable is a symbol that stands for a number. A symbol or letter representing an unknown member of a set. In algebraic expressions, a variable stands for a value. Sometimes it is called an unknown. The same variable may have different values under different conditions. &quot;Since you have posted a question with multiple sub-parts, we will solve the first four sub-parts for you. To get the remaining sub-part solved, please repost the complete question and mention the sub-parts to be solved.&quot; 1) Cancel the common factor 4 and simplifying m3m−3 gives m6 and n3n2 is n using the rule ab=ab−1 4m3n34m−3n2=m3n3m−3n2 =m3−(−3)⋅n3−2 =m6n 2) Apply the rule a0=1 where a≠0 3mn44m0=3mn44⋅1 =3mn44 3) Apply the exponent rule a0=1 where a≠q0; cancel out the common factor 3 and u−2u−1 is 1u. 3u−23u−1v0=3u−23u−1⋅1 =3u−23u−1 =u−2{u−1} =u−2−(−1) =u−2+1 =u−1 3u−23u−1v0=1u 4) Apply the fraction rule −a−b=ab −a−6b−5−2b2⋅(a3b−3)6=a−6b−52b2(a3b−3)6 =a−62b2+5

1) \frac{4m^{3}n^{3}}{4m^{-3}n^{2}} 2) \frac{3mn^{4}}{4m^{0}} NS

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