Solve by the method of elimination. 1. x−3y=2 2x+3y=13 2. 3x+10y=2 x−2y=−6 3. 3x+2y=12 3x−y=3

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Solve by the method of elimination.  1. x−3y=2  2x+3y=13  2. 3x+10y=2  x−2y=−6  3. 3x+2y=12  3x−y=3

Corben Pittman · Accepted Answer

Step 1  In algebra, an equation can be defined as a mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value. The most basic and common algebraic equations in math consist of one or more variables. For instance, 4x+6=30 is an equation, in which 4x+6 and 30 are two expressions separated by an ‘equal’ sign.  In an algebraic equation, the left-hand side is equal to the right-hand side.  Step 2  First of all rearrange the first equation x−3y=2 by separating the variable x on one side of the equation and rest on other side of the equation.  x−3y=2  x=2+3y  And now substitute the value of x from above equation and substitute the value in second equation that is 2x+3y=13, to obtain the value of y.  2x+3y=13  2(2+3y)+3y=13  4+6y+3y=13  9y=13−4  y=99  =1  Step 3  And now substitute y as 1 in the first equation x−3y=2 to obtain the value of x.  x−3y=2  x=2+3×1  =5  Therefore the value of solution of the system of equation is (5,1)

Solve by the method of elimination. 1. x-3y=2 2x+3y=13 2

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