Solve algebraically for x −23(x+12)+23x=−54x+2

Question

Solve algebraically for x  −23(x+12)+23x=−54x+2

cheekabooy · Accepted Answer

Step 1
The addition or subtraction between two like fractions can be done by adding or subtracting the numerators of both fractions by fixing the same denominator to the result. Like fractions are the fractions with the same denominator.
For addition or subtraction between two unlike fractions, we have to convert both denominators of the fractions to the same value. This can be done by finding the LCM (Least Common Multiple) of the denominators of the fractions. We can multiply and divide both the fractions by a suitable constant to produce the same value in both the denominators.
Step 2
To find the value of x , we have to isolate the variable term (x) to one side of the equation.
We have,

- \frac{2}{3} (x + 12) + \frac{2}{3} x = - \frac{5}{4} x + 2

We have to simplify the expression. Multiply the terms to inside the bracket simlify

- \frac{2}{3} x - \frac{2}{3} \times 12 + \frac{2}{3} x = - \frac{5}{4} x + 2

- 8 = - \frac{5}{4} x + 2

- 8 = \frac{- 5 x + 8}{4}

- 8 \times 4 = - 5 x + 8

- 32 - 8 = - 5 x

- 40 = - 5 x

\frac{- 40}{- 5} = x

8 = x

Hence, the value of x is 8.

Solve algebraically for x -\frac{2}{3}(x+12)+\frac{2}{3}x=-\frac{5}{4}x+2

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