Answered: "Find the sum by converting the mixed numbers..."

aidmoong7

Answered question

2021-11-14

Find the sum by converting the mixed numbers to improper fractions:

3 \frac{7}{10} + 2 \frac{9}{10}

Answer & Explanation

Provere

Beginner2021-11-15Added 18 answers

Calculation:
Given

3 \frac{7}{10} + 2 \frac{9}{10}

,
Writing the mixed numbers as improper functions,

3 \frac{7}{10} + 2 \frac{9}{10} = \frac{10 (3) + 7}{10} + \frac{10 (2) + 9}{10}

3 \frac{7}{10} + 2 \frac{9}{10} = \frac{30 + 7}{10} + \frac{20 + 9}{10}

3 \frac{7}{10} + 2 \frac{9}{10} = \frac{37}{10} + \frac{29}{10}

To add or subtract rational numbers the denominators need to be equal.
When the denominators are equal, the numerators can be added or subtracted as per the operation.
Hence,

3 \frac{7}{10} + 2 \frac{9}{10} = \frac{37 + 29}{10}

3 \frac{7}{10} + 2 \frac{9}{10} = \frac{66}{10}

To convert the improper fraction to mixed fraction, the numerator is written as sum of a multiple of denominator and the remainder.

3 \frac{7}{10} + 2 \frac{9}{10} = \frac{60 + 6}{10}

3 \frac{7}{10} + 2 \frac{9}{10} = \frac{60}{10} + \frac{6}{10}

3 \frac{7}{10} + 2 \frac{9}{10} = 6 + \frac{6}{10}

3 \frac{7}{10} + 2 \frac{9}{10} = 6 \frac{6}{10}

Therefore,

3 \frac{7}{10} + 2 \frac{9}{10} = 6 \frac{6}{10}

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Pre-Algebra

Didn't find what you were looking for?