To calculate: The calcium present in 1 cup of milk and in 1 cup of coo

vetrila10

vetrila10

Answered question

2021-11-17

To calculate: The calcium present in 1 cup of milk and in 1 cup of cooked spinach if one day Shenika had 3 cups of milk and 1 cup of cooked spinach for a total of 1140 mg of calcium. The next day, she had 2 cups of milk and 112 cups of cooked spinach for a total of 960 mg of calcium.

Answer & Explanation

Coon2000

Coon2000

Beginner2021-11-18Added 15 answers

Calculation:
Consider that Shenika had 3 cups of milk and 1 cup of cooked spinach for a total of 1140 mg of calcium. The next day, she had 2 cups of milk and 112 cups of cooked spinach for a total of 960 mg of calcium.
Convert this problem into two system of equations.
Let the amount of calcium present in 1 cup of milk be x mg and the amount of calcium present in 1 cup of cooked spinach be y mg.
Shenika had 3 cups of milk and 1 cup of cooked spinach for a total of 1140 mg of calcium.
Now, this can be represented by a linear equation which is as follows,
3x+y=1140.....(1)
The next day, she had 2 cups of milk and 112cups of cooked spinach for a total of 960 mg of calcium.
Now, this can be represented by a linear equation which is as follows,
2x+1.5y=960
Multiply with 10 to clear decimals of above equation.
20x+15y=9600......(2)
4x+3y=1920
So, the system of equation becomes as,
3x+y=1140
4x+3y=1920
Now, multiply the first equation with -3.
9x3y=3420
4x+3y=1920
Add these equations and solve for x.
9x+4x3y+3y=3420+1920
5x=1500
x=15005
x=300
Substitute 300 for x in the (1) equation and solve for y.
3(300)+y=1140
900+y=1140
y=1140900
y=240
Substitute the ordered pair in each equation to verify the system of equation.
Substitute (x,y)=(300,240) in first equation.
3300+240=?1140
900+240=?1140
1140=1140
The result is true.
Substitute (x,y)=(300,240) in second equation.
4300+240=?1920
1200+720=?1920
1920=1920
The result is true.
Therefore, the calcium present in 1 cup of milk is 300 mg and in 1 cup of cooked spinach is 240 mg.

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