The sum of two numbers. Given: Two consecutive numbers are: 6x6(x+1)=89. Two consecutive multiples of 6 are a ratio of 8:9. 6x6(x+1)=89.

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The sum of two numbers.  Given:  Two consecutive numbers are: 6x6(x+1)=89.  Two consecutive multiples of 6 are a ratio of 8:9. 6x6(x+1)=89.

Robert Pina · Accepted Answer

Calculation:  In order to solve the given equation 6x6(x+1)=89 for the variable, isolate the variable term x on one side by performing some basic algebraic operations to get rid of the other numbers are terms associated with it.  Here to isolate x on both side, first multiply both sides by 9 and then multiply both sides by 6(x+1) and then subtract both sides by 48x simplify the like terms and then simplify further divide both sides by 6 as shown below,  6x6(x+1)=89  6x6(x+1)⋅9=89⋅9  546(x+1)=8  546(x+1)⋅6(x+1)=8⋅6(x+1)  54x=48(x+1)  54x=48x+48  54x−48x=48x+48−48x  6x=48  6x6=486  x=8  So the required numbers will be  6x=6⋅8=48  and 6(x+1)=6(8+1)=54  Thus, the sum of two numbers is 48+54=102.

Kayla Kline · Accepted Answer

Step 1 6x6(x+1)=89 Variable x cannot be equal to −1 since division by zero is not defined. Multiply both sides of the equation by 18(x+1), the least common multiple of 6(x+1), 9. 3×6x=16(x+1) Multiply 3 and 6 to get 18. 18x=16(x+1) Use the distributive property to multiply 16 by x+1. 18x=16x+16 Subtract 16x from both sides. 18x−16x=16 Combine 18x and −16x to get 2x. 2x=16 Divide both sides by 2. x=162 Divide 16 by 2 to get 8. x=8 6x=6×8=48 6(x+1)=6(8+1)=54 48+54=102 Answer: the sum of two numbers is 102

The sum of two numbers. Given: Two consecutive numbers are: \frac{6x}{6(x+1)}=\frac{8}{9}. Two consecutive

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