We have an answer to "How do you factor 20x5−5"

hunterofdeath63

Answered question

2021-12-18

How do you factor

20 x^{5} - 5

nghodlokl

Beginner2021-12-19Added 33 answers

20 x^{5} - 5 = 5 (4 x^{2} - 1) = 5 (2 x - 1) (2 x + 1)

Explanation:
So we have

20 x^{2} - 5 = 5 (4 x^{2} - 1)

; dividing thru by 5

5 (4 x^{2} - 1)

And

4 x^{2} - 1

is the difference between 2 squares,

2 x

and 1

(4 x^{2} - 1) = (2 x - 1) (2 x + 1)

Putting it all together:

20 x^{2} - 5 = 5 (2 x - 1) (2 x + 1)

So there are roots at

\pm \frac{1}{2}

Travis Hicks

Beginner2021-12-20Added 29 answers

20 x^{2} - 5

Factor 5 out of

20 x^{2} - 5

5 (4 x^{2} - 1)

Rewrite

4 x^{2}

{(2 x)}^{2} .

5 ({(2 x)}^{2} - 1)

Rewrite

1

1^{2}

5 ({(2 x)}^{2} - 1^{2})

5 (2 x + 1) (2 x - 1)

RizerMix

Expert2021-12-29Added 656 answers

Hi, Does anybody know how to do this question? Thank-you

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