Resolved: "Find the prime factorization of 72."

High School
Algebra
Pre-Algebra
Factors and multiples

jubateee

Answered question

2021-12-21

Find the prime factorization of 72.

Answer & Explanation

boronganfh

Beginner2021-12-22Added 33 answers

Firstly, divide the number to be factored by the prime numbers in turn. Test that result is a natural number. If so, it is a prime factor and, therefore, continue until the factorisation is complete.
72 is even, so 2 is a factor and we have 36, which is also even, so we have another factor. Then 18 also has 2 as a factor, but 9 has only 3 as a factor, and 3 has also 3 as a fsctor. Hence, the prime factors are:

2 \times 2 \times 2 \times 3 \times 3 = 2^{3} \times 3^{2}

Becky Harrison

Beginner2021-12-23Added 40 answers

Divide 72 by 2:

\frac{72}{2} = 36

Divide 36 by 2

\frac{36}{2} = 18

Divide 18 by 2

\frac{18}{2} = 9

Divide 9 by 3

\frac{9}{3} = 3

Divide 3 by 3

\frac{3}{3} = 1

Thus, we have the prime factorization:

2 \times 2 \times 2 \times 3 \times 3

RizerMix

Expert2021-12-29Added 656 answers

The prime factorization of 72 is:
$2 \times 2 \times 2 \times 3 \times 3$

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