Check the solution to "solve x−15≥12"

regatamin2

Answered question

2021-12-26

solve

x - \frac{1}{5} \geq \frac{1}{2}

Jacob Homer

Beginner2021-12-27Added 41 answers

x - \frac{1}{5} \geq \frac{1}{2}

\Rightarrow x - \frac{1}{5} + \frac{1}{5} \geq \frac{1}{2} + \frac{1}{5}

\Rightarrow x \geq \frac{7}{10}

Bubich13

Beginner2021-12-28Added 36 answers

x - \frac{1}{5} \geq \frac{1}{2}

Add

\frac{1}{5}

to both sides of the inequality.

X \geq \frac{1}{2} + \frac{1}{5}

To write

\frac{1}{2}

as a fraction with a common denominator, multiply by

\frac{5}{5}

x \geq \frac{1}{2} \cdot \frac{5}{5} + \frac{1}{5}

To write

\frac{1}{5}

as a fraction with a common denominator, multiply by

\frac{2}{2}

x \geq \frac{1}{2} \cdot \frac{5}{5} + \frac{1}{5} \cdot \frac{2}{2}

Write each expression with a common denominator of 10, by multiplying each by an appropriate factor of 1.

x \geq \frac{5}{10} + \frac{2}{10}

Combine the numerators over the common denominator.

x \geq \frac{5 + 2}{10}

Add 5 and 2

x \geq \frac{7}{10}

The result can be shown in multiple forms. Inequality Form:

x \geq \frac{7}{10}

Interval Notation:

[\frac{7}{10}, \infty)

karton

Expert2021-12-30Added 613 answers

$x - \frac{1}{5} \geq \frac{1}{2}$
so $x \geq \frac{1}{2} + \frac{1}{5}$
$x \geq \frac{7}{11}$

Do you have a similar question?

Recalculate according to your conditions!

Didn't find what you were looking for?