A person invests $2500 in an account at 6% interest compounded annually. Let V=f(t) be the value (in dollars) of the account after t years or any fraction thereof. a. Find an equation of f. b. What is the V-intercept? What does it mean in this situation? c. What will be the value of the investment in six years? d. When will the value of the investment be $7000?

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A person invests $2500 in an account at 6% interest compounded annually. Let V=f(t) be the value (in dollars) of the account after t years or any fraction thereof.  a. Find an equation of f.  b. What is the V-intercept? What does it mean in this situation?  c. What will be the value of the investment in six years?  d. When will the value of the investment be $7000?

enhebrevz · Accepted Answer

Given that  P=$2500  time =t years  rate =6%  Principal rate =$2500  Rate =6% compomoted annualy  time =t (general)  using formula  v=f(t)−p(1+∂n)nt  ⇒2500(1+6100)t  A) [v=f(t)⇒2500(1.06)t]  B) The v-intercept  (x,y)=(0,2500)  This indicate the original investment was  2500 Dollars   C) at t=6 year  v=2500(1.06)6  v=3546.297 (Dollars)  D) The time at which value will $7000.  7000=2500(1.06)t  7025=(1.06)t  Taking log both sides  ln⁡145=tln⁡(1.06)⇒t=1.0296190.58268  t=17.670 years

deginasiba · Accepted Answer

A=P(1+rn)nt  A= the future value of the investment/loan, including interest   P= the principal investment amount (the initial deposit   r= the annual interest rate (decimal) (6100=(0.06))  n= the number of times that interest is compounded per month (2)   [In a year interest is compounded 24]   t= the number of years the money is invested (4)  A=2500(1+0.624)4×24  A=2500(1.025)96=2500(10.7)=26,750  Money in the account after 4 years =26,750

A person invests $2500 in an account at 6% interest compounded annually. Let V=f(t) be the val

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