How do you evaluate x3−2y2−3x3+z4 if x=3,y=5, and z=−3?

Step 1 By substituting the given numeric values for x,y and z into the expression. That is (3)3−2(5)2−3(3)3+(−3)4 Step 2 I'll evaluate each term separately. (3)3=3×3×3=9×3=27 2(5)2=2×(5×5)=2×25=50 3(3)3=3×(3×3×3)=3×27=81 (−3)4=[(−3)×(−3)]×[(−3)×(−3)]=9×9=81 Step 3 Replace these values back into the expression , noting the values which are subtracted. ⇒27−50−⧸81+⧸81=27−50=−23

"How do you evaluate x3−2y2−3x3+z4 if x=3,y=5, and..." was answered by our experts

High School
Algebra
Pre-Algebra
Equations, expressions, and inequalitie

Sergio Bradshaw

Answered question

2022-02-02

How do you evaluate

x^{3} - 2 y^{2} - 3 x^{3} + z^{4}

x = 3, y = 5

, and

z = - 3

Answer & Explanation

Macey Mata

Beginner2022-02-03Added 13 answers

Step 1
By substituting the given numeric values for x,y and z into the expression.
That is
${(3)}^{3} - 2 {(5)}^{2} - 3 {(3)}^{3} + {(- 3)}^{4}$
Step 2
I'll evaluate each term separately.
${(3)}^{3} = 3 \times 3 \times 3 = 9 \times 3 = 27$
$2 {(5)}^{2} = 2 \times (5 \times 5) = 2 \times 25 = 50$
$3 {(3)}^{3} = 3 \times (3 \times 3 \times 3) = 3 \times 27 = 81$
${(- 3)}^{4} = [(- 3) \times (- 3)] \times [(- 3) \times (- 3)] = 9 \times 9 = 81$
Step 3
Replace these values back into the expression , noting the values which are subtracted.
$\Rightarrow 27 - 50 - ⧸ 81 + ⧸ 81 = 27 - 50 = - 23$

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