How do you evaluate h(x)=-\frac{5}{3}|x|+6 \text{for}\ x=-2?

Rodrigo Underwood

Rodrigo Underwood

Answered question

2022-02-03

How do you evaluate h(x)=53|x|+6for x=2?

Answer & Explanation

patriette65s

patriette65s

Beginner2022-02-04Added 15 answers

h(x)=133at x=2
Explanation:
h(x) is just a way of writing "a function (call it h) in x", meaning whatever is on the other side of the equation. Given a particular value (-2) you just put it into the equation and solve it.
h(x)=(53)|x|+6
h(x)=(106)+6;h(x)=(106)+366
h(x)=266;h(x)=133 or 4.33

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