Answered: "How do you evaluate (2g−1)2−2g+g2for g=3?"

realenishb0

Answered question

2022-02-03

How do you evaluate

{(2 g - 1)}^{2} - 2 g + g^{2} for g = 3

utripljigmp

Beginner2022-02-04Added 12 answers

Solution:
Putting

g = 3 in {(2 g - 1)}^{2} - 2 g + g^{2}

.
we get

{(2 \times 3 - 1)}^{2} - 2 \times 3 + 3^{2}

= {(6 - 1)}^{2} - 6 + 9

= 5^{2} + 3

25 + 3

Hence, 28.

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