F(x)=x2+6x+8? 1. What are the x and y intercepts for this equation? 2. What is the vertex of this equation?

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F(x)=x2+6x+8?  1. What are the x and y intercepts for this equation?  2. What is the vertex of this equation?

Heidy Prince · Accepted Answer

1. What are the x and y intercepts for this equation? a) The y intercept is the value of the equation when x=0 In this case if x=0 F(0)=02+6×0+8=8 So the y intercept is 8 b) The x intercepts are the values of x for which the equation is equal to 0 In this case if x2+6x+8=0 We can factor the expression on the left: (x+2)(x+4)=0 (x+2)=0or (x+4)=0 →x=−2→x=−4 So the x intercepts are (-2) and (-4)

Michaela Boyle · Accepted Answer

2. What is the vertex of this equation?  We can convert this equation into vertex form: F(x)=(x−a)2+b with vertex at (a, b).  F(x)=x2+6x+8  =x2+6x+9−1  =(x+3)2−1  =(x−(−3))2+(−1)  which is the vertex form with vertex at (−3−1)

F(x)=x^{2}+6x+8? 1. What are the x and y intercepts for this

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