Answered: "How to solve 12+x3+x24 where x=12?"

m1cadc

Answered question

2022-02-05

How to solve

\frac{1}{2} + \frac{x}{3} + \frac{x^{2}}{4}

where

x = \frac{1}{2}

Emilie Mcpherson

Beginner2022-02-06Added 12 answers

Given:

\frac{1}{2} + \frac{x}{3} + \frac{x^{2}}{4} with x = \frac{1}{2}

\frac{1}{2} + \frac{\frac{1}{2}}{3} + \frac{{(\frac{1}{2})}^{2}}{4}

= \frac{1}{2} + \frac{\frac{1}{2}}{3} + \frac{\frac{1}{4}}{4}

= \frac{1}{2} + \frac{1}{2} \cdot \frac{1}{3} + (\frac{1}{4}) \cdot \frac{1}{4}

= \frac{1}{2} + \frac{1}{6} + \frac{1}{16}

least common multiple is

3 \times 16 = 48

\frac{1}{2} + \frac{1}{6} + \frac{1}{64}

= \frac{24}{48} + \frac{8}{48} + \frac{35}{48}

= \frac{35}{48}

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