How do you write the inequality and solve given "twice a number increased by 3 is less than the number decreased by 4"?

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How do you write the inequality and solve given &quot;twice a number increased by 3 is less than the number decreased by 4&quot;?

empatteMattmkezo · Accepted Answer

Step 1To write the inequality we will start by defining &quot;a number&quot; as n.Then, &quot;twice a number&quot; can be written as 2n.&quot;increased by 3&quot; becomes:       2    n    +    3  &quot;is less than&quot; turns it into&quot;       2    n    +    3    &amp;lt;  &quot;the number decreased by 4&quot; is:       n    -    4  Putting this together gives the inequality:      2    n    +    3    &amp;lt;    n    -    4  To solve, first subtract                     3             and                     n             from each side of the inequality to solve for n while keeping the inequality balanced:      -                  n              +    2    n    +    3    -                  3              &amp;lt;    -                  n              +    n    -    4    -                  3                  -                  1        n              +    2    n    +    0    &amp;lt;    0    -    7

How do you write the inequality and solve given "twice

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