Find the fraction where the decimal expansion is infinite? Find the fraction with integers for the

britesoulusjhq

britesoulusjhq

Answered question

2022-05-14

Find the fraction where the decimal expansion is infinite?
Find the fraction with integers for the numerator and denominator, where the decimal expansion is 0.11235.....
The numerator and denominator must be less than 100.
Find the fraction
I believe I can use generating functions here to get 1 + x + 2 x 2 + 3 x 3 + 5 x 4 + . . . . . but I do not know how to apply it.

Answer & Explanation

Kyler Crawford

Kyler Crawford

Beginner2022-05-15Added 16 answers

Like you hint, we can observe that the value
0.11235955056 = k = 1 10 k F k ,
where F k is the kth Fibonacci number (with the convention that F 0 = 0, F 1 = 1), is simply the value of the series
F ( x ) := k = 1 F k x k = x + x 2 + 2 x 3 + 3 x 4 + 5 x 5 + 8 x 6 + 13 x 7 +
at x = 1 10
Hint Using the defining recurrence relation
F k + 2 = F k + 1 + F k
(and the above convention) gives that F(x) satisfies
F ( x ) = x + x F ( x ) + x 2 F ( x ) .
Rearranging gives that on the open interval of convergence of the series, which turns out to be ( 1 / ϕ , 1 / ϕ ) ---where ϕ is the Golden Ratio, and which in particular contains the value 1 10 of interest)---we have
F ( x ) = x 1 x x 2 .
Thus, the series has value
F ( 1 10 ) = ( 1 10 ) 1 ( 1 10 ) ( 1 10 ) 2 = 10 89 .
Since this is a rational number, its decimal expansion repeats:
0. 1123595505617977528089887640449438202247191 ¯ .
syaoronsangelhwc17

syaoronsangelhwc17

Beginner2022-05-16Added 4 answers

Continued fractions:
11235 100000 = 2247 20000 = 1 8 + 2024 2247 = 1 8 + 1 1 + 223 2024 = 1 8 + 1 1 + 1 9 + 1 13 + 2 17 = 1 8 + 1 1 + 1 9 + 1 13 + 1 8 + 1 2 = [ 0 ; 8 , 1 , 9 , 13 , 2 ]
The first convergent is 1/8; the second convergent is
1 8 + 1 = 1 9 ;
the third convergent is
1 8 + 1 1 + 1 9 = 1 8 + 9 10 = 10 89 ;
The fourth convergent can be computed to 131/1166

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