Solve fractions multiplication I believe this is a very simple one, but I simply can't figure it ou

Davin Fields

Davin Fields

Answered question

2022-05-21

Solve fractions multiplication
I believe this is a very simple one, but I simply can't figure it out. How to solve?
1 2 3 4 5 6 17 18 19 20

Answer & Explanation

Arianna Turner

Arianna Turner

Beginner2022-05-22Added 12 answers

The general compact writing of this sort of fraction is
1 3 5 ( 2 n 1 ) 2 4 6 2 n = ( 2 n ) ! ( 2 4 6 2 n ) 2 = ( 2 n ) ! 2 2 n ( n ! ) 2 = 1 2 2 n ( 2 n n ) .
Waylon Ruiz

Waylon Ruiz

Beginner2022-05-23Added 7 answers

Bernard gave the compact formula
A n = 1 3 5 ( 2 n 1 ) 2 4 6 2 n = ( 2 n ) ! 2 2 n ( n ! ) 2
Now, let me assume that you have large values of n and that you need a shortcut approximation of the result in a decimal form.
The factorial can be evaluated using Stirling approximation
p ! 2 π p ( p e ) n
Applying it to A n gives
A n 1 π n
Applied to n = 10 as in your post, this will give a value of 0.178412 while the true value would be 0.176197 which is not too bad (I hope). If you want something better, take an extra term in Stirling formula to get
A n 1 π n ( 1 1 8 n )
which would give 0.176182

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