Adding 1 to a/b? I've been learning algebra 2 and came across a question telling me to add

Sturmboot0ae2a

Sturmboot0ae2a

Answered question

2022-06-03

Adding 1 to a/b?
I've been learning algebra 2 and came across a question telling me to add 1 to a b by finding the least common multiple of the divisors. So I got 1 b 1 b + a b that simplified is b b + a b . So then I added those two fractions together and got a b b I saw that the two b's cancelled each other out so I got a 1 which is a? How does adding 1 to a b get a, this doesn't seem to be right because 1 + 2 3 isn't 2 it's 1 and 2 3 . Am I doing something wrong or is this actually correct, if so can you explain to me why?

Answer & Explanation

try100hkda8mm

try100hkda8mm

Beginner2022-06-04Added 3 answers

"...that simplified is b/b+a/b. So then I added those two fractions together and got ab/b .."
That shouldn't make any sense and if I saw your paper I may understand why you did it. But it's simply wrong.
1 + a b
1 b 1 b + a b
b b + a b You are right so far so let's add these.
b + a b ... and I don't know why you added a + b to get ab (probably a misplaced mark on the scratch paper). The final answer is b + a b
===== " its a+b/b which is a+1 when simplified".
Oooh, no. Both the a and the b are over the b. You can't cancel out just one.
a + b b a + b b
You can factor the b out of both but then you get
a + b b = a / b + 1 1 = a b + 1 but then you have worked yourself back to exactly where you started.
Brayan Herring

Brayan Herring

Beginner2022-06-05Added 2 answers

"So I got 1b/1b+a/b that simplified is b/b+a/b. So then I added those two fractions together and got ab/b"
You have figured out correctly up to this point:
b b + a b
The next step in your statement is where the error made. Since the denominators are equal, you just add the numerators and divide by the common denominator to get:
b b + a b = b + a b
The general rule is (where x and y are not zero)is:
A x + B y = A y + B x x y

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