I am aware that using the counting measure on Lebesgue you can get important results. I am wondering

Jasmin Pineda

Jasmin Pineda

Answered question

2022-06-16

I am aware that using the counting measure on Lebesgue you can get important results. I am wondering if there is a way to exchange the limits using Dominated Convergence Theorem.
Let a n , m be indexed from 0 to infinity. | a n , m | < M for all indexes. lim m a n , m exists for all m.
Does DCT allow you do say lim n lim m a n , m = lim m lim n a n , m

Answer & Explanation

Marlee Norman

Marlee Norman

Beginner2022-06-17Added 18 answers

MathJax(?): Can't find handler for document MathJax(?): Can't find handler for document No. Take, for instance,
a n m = { 1  if  m n 0 otherwise.
It's bounded, but
lim n lim m a n m = 1 and lim m lim n a n m = 0.

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