Find the limit of fraction involving logarithms I am looking for a way to prove the following limit

Ayanna Trujillo

Ayanna Trujillo

Answered question

2022-06-15

Find the limit of fraction involving logarithms
I am looking for a way to prove the following limit for integer xs:
lim x log ( x + 2 ) log ( x + 1 ) log ( x + 2 ) log ( x ) = 1 2
I could find the result by using a computer program but I cannot formally establish the above equality.

Answer & Explanation

Nia Molina

Nia Molina

Beginner2022-06-16Added 21 answers

You may write, as x
log ( x + 2 ) log ( x + 1 ) log ( x + 2 ) log ( x ) = log ( 1 + 2 x ) log ( 1 + 1 x ) log ( 1 + 2 x ) = 1 x + O ( 1 / x 2 ) 2 x + O ( 1 / x 2 ) = 1 2 + O ( 1 / x ) .
Izabella Ponce

Izabella Ponce

Beginner2022-06-17Added 4 answers

The Mean Value Theorem says,
log ( x + 2 ) log ( x + 1 ) log ( x + 2 ) log ( x ) = 1 2 log ( x + 2 ) log ( x + 1 ) 1 log ( x + 2 ) log ( x ) 2 = 1 2 1 ξ 1 1 ξ 0 = 1 2 ξ 0 ξ 1
where x + 1 < ξ 1 < x + 2 and x < ξ 0 < x + 2. Therefore,
1 2 x x + 2 log ( x + 2 ) log ( x + 1 ) log ( x + 2 ) log ( x ) 1 2 x + 2 x + 1
The Squeeze Theorem, then says that
lim x log ( x + 2 ) log ( x + 1 ) log ( x + 2 ) log ( x ) = 1 2

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