I am currently working on a problem from my statistics class. It is as follows: A computer consulting firm presently has bids out on three projects. Let A 1 = { awarded project i } , for i = 1 , 2 , 3 , and suppose that P ( A 1 ) = .22 , P ( A 2 ) = .25 , P ( A 3 ) = .23 , P ( A 1 ∩ A 2 ∩ A 3 ) = .01 . Expree in words each of th following events, and compute the probability of each event : a . A 1 ∪ A 2 b . A 1 ′ ∩ A 2 ′ c . A 1 ∪ A 2 ∪ A 3 e . A 1 ′ ∩ A 2 ′ ∩ A 3 d . A 1 ′ ∩ A 2 ′ ∩ A 3 ′ f . ( A 1 ′ ∩ A 2 ′ ) ∪ A 3 The only one I had difficulty quantifying with words was problem f). How would I do that?Also, I had originally assumed the three events were disjoint; but, by looking at the question again, I found that they aren't, because of the last piece of information given--the intersection of all of the events. I am having a hard time understanding how they are not disjoint. How can these particular three events have something in common? It just seems odd.

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I am currently working on a problem from my statistics class. It is as follows:  A computer consulting firm presently has bids out on three projects. Let      A    1    =  {  awarded project  i  }  ,  for  i  =  1  ,  2  ,  3  ,   and suppose that   P  (      A    1    )  =  .22  ,    P  (      A    2    )  =  .25  ,    P  (      A    3    )  =  .23  ,    P  (      A    1    ∩      A    2    ∩      A    3    )  =  .01  .    Expree in words each of th following events, and compute the probability of each event  :    a  .      A    1    ∪      A    2      b  .      A    1    ′  ∩      A    2    ′    c  .      A    1    ∪      A    2    ∪      A    3      e  .      A    1    ′  ∩      A    2    ′  ∩      A    3      d  .      A    1    ′  ∩      A    2    ′  ∩      A    3    ′    f  .  (      A    1    ′  ∩      A    2    ′  )  ∪      A    3  The only one I had difficulty quantifying with words was problem f). How would I do that?Also, I had originally assumed the three events were disjoint; but, by looking at the question again, I found that they aren&#039;t, because of the last piece of information given--the intersection of all of the events. I am having a hard time understanding how they are not disjoint. How can these particular three events have something in common? It just seems odd.

Abigail Palmer · Accepted Answer

How can these particular three events have something in common?If you assume they are disjoint, that means that if the consulting firm gets Project 1 they can&#039;t possibly also get Project 2 or Project 3. That&#039;s a strong assumption! Why should getting Project 1 keep them from also getting a contract for Project 2?As for the one you were having trouble interpreting, we have  (      A    1    ′    ∩      A    2    ′    )  ∪      A    3    .      A    1    ′   means they did not get Project 1, similarly for       A    2    ′  . So this statement says &quot;They failed to get both Project 1 and Project 2, or they got Project 3.&quot; And remember that the &quot;or&quot; is not exclusive.

I am currently working on a problem from my statistics class. It is as follows: <mtext>A compute

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