If we have a question where we have to find the coefficient's units such as K in this case. The actual formula contains more parts but it is simply the derivatives that I am unsure about. K = d v d t Where v = m s − 1 (metres per second) and t is timeDo I simply find the derivative of m s − 1 in respect to s? And whatever units of measurement I am left with are the units of K? ie. d ( m s − 1 ) d s = m ∗ d ( s − 1 ) d s = − m s − 2

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If we have a question where we have to find the coefficient&#039;s units such as K in this case. The actual formula contains more parts but it is simply the derivatives that I am unsure about.  K  =            d      v              d      t      Where   v  =  m      s          −      1       (metres per second) and t is timeDo I simply find the derivative of   m      s          −      1       in respect to s? And whatever units of measurement I am left with are the units of K? ie.            d      (      m              s                  −          1                    )              d      s        =  m  ∗            d      (              s                  −          1                    )              d      s        =  −  m      s          −      2

Haggar72 · Accepted Answer

No, you just divide by the unit of time. The derivative is defined as a limit of a difference quotient: (velocity difference)/(time difference). This quotient has units (m/s)/s, and taking the limit doesn&#039;t change the unit.

If we have a question where we have to find the coefficient's units such as K in this case. The actu

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