Simplifying a fraction with a cubed root in the denominator I have an equation the following equati

Averi Mitchell

Averi Mitchell

Answered question

2022-06-25

Simplifying a fraction with a cubed root in the denominator
I have an equation the following equation in my textbook, but I don't understand how it's legal for it to be simplified this way.
1000 π 500 π 3 2 = 2 500 π 3
I know that an equivalent equation is
1000 π 500 π 2 / 3 = 1000 π ( 500 π ) 1 / 3 ( 500 π ) 1 / 3
Looking at it I can see where things might cancel, like in one of the 500 π 1 / 3 , the 500 could go into 1000 twice, and cancel out the π in the denominator, but as far as I can remember that's not allowed.
Why is this okay?

Answer & Explanation

Odin Jacobson

Odin Jacobson

Beginner2022-06-26Added 17 answers

Hint:
multiply numerator and denominator for:
500 π 3
Alannah Short

Alannah Short

Beginner2022-06-27Added 5 answers

Rewrite:
1000 π 500 π 3 2 = 1000 π × ( 500 π ) 2 / 3
And note:
1000 π = 2 ( 500 π ) 3 / 3

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