Oakey1w

2022-06-27

Suppose that the Hilbert space of a quantum-mechanical system - which we will call the quantum door - is generated by two states, |open> and |closed>, forming an orthonormal basis. Suppose also that the system is prepared in the state

$|\psi (x)>=\frac{1}{\sqrt{5}}(|OPEN>+2|CLOSED>)$ We are given a device that measures whether the quantum door is open or closed.

(i)If we perform a measurement, which probability do we have to find the quantum door open?

(ii) Suppose the measurement returns that the quantum door is closed, and assume that the quantum Hamiltonian is identically 0 for this system at any future times. Does the door stay closed forever?

For part (i) I get

${P}_{Open}=(<open|\frac{1}{\sqrt{5}}(|OPEN>+2|CLOSED>{)}^{2}$ = 1/5 ?

I also need help with part (ii), i am unure about this.

$|\psi (x)>=\frac{1}{\sqrt{5}}(|OPEN>+2|CLOSED>)$ We are given a device that measures whether the quantum door is open or closed.

(i)If we perform a measurement, which probability do we have to find the quantum door open?

(ii) Suppose the measurement returns that the quantum door is closed, and assume that the quantum Hamiltonian is identically 0 for this system at any future times. Does the door stay closed forever?

For part (i) I get

${P}_{Open}=(<open|\frac{1}{\sqrt{5}}(|OPEN>+2|CLOSED>{)}^{2}$ = 1/5 ?

I also need help with part (ii), i am unure about this.

tennispopj8

Beginner2022-06-28Added 20 answers

You got the part (i) correct. The probability of the door being measured as 'Open' is 1/5.

On the part (ii), the door will stay as 'Closed' after being measured as in 'Closed' state. It will change only if the system is interacted by other operations.

On the part (ii), the door will stay as 'Closed' after being measured as in 'Closed' state. It will change only if the system is interacted by other operations.

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