Express w and 1 / w for w = 2 + 3 5 − 3 in the simplest form with a rational denominatorExpress the following in the simplest form (with a rational denominator)i) wii) 1 w I'm confused about (ii) question :/ pls help me.

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Express   w and   1      /    w for   w  =                    2            +              3                            5            −              3             in the simplest form with a rational denominatorExpress the following in the simplest form (with a rational denominator)i)   wii)       1    w  I&#039;m confused about (ii) question :/ pls help me.

Jayvion Mclaughlin · Accepted Answer

If   w  =                    2            +              3                            5            −              3            , then       1    w    =                    5            −              3                            2            +              3             If you can do i, you should be able to do ii. The process is the same.

klipbodok6 · Accepted Answer

w                            =                                            2                        +                          3                                                          5                        −                          3                                                                        =                              (                          2                        +                          3                        )            (                          5                        +                          3                        )                                (                          5                        −                          3                        )            (                          5                        +                          3                        )                                                            =                              3            +                          6                        +                          10                        +                          15                                            5            −            3                                                            =                  1          2                (        3        +                  6                +                  10                +                  15                )                                      1          w                                    =                                            5                        −                          3                                                          2                        +                          3                                                                        =                              (                          5                        −                          3                        )            (                          3                        −                          2                        )                                (                          2                        +                          3                        )            (                          3                        −                          2                        )                                                            =                                            15                        −                          10                        +                          6                        −            3                                3            −            2                                                            =                  15                −                  10                +                  6                −        3

Express w and 1 <mrow class="MJX-TeXAtom-ORD"> / </mrow> w for w =

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