If the chance of an event was 1 / 128 and increased by 20%, what is the new chance?So I have something that has a 1/128 chance of occurring, let's say. Suddenly, the chances of that thing happening are increased by 20%. How is that fraction written? Would you multiply 1/128 by 6/5 (yielding 3/320), or would you take 128, multiply it by 4/5, and then invert it (1/102)?This isn't for homework, I'm merely curious.Thank you

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If the chance of an event was   1      /    128 and increased by 20%, what is the new chance?So I have something that has a 1/128 chance of occurring, let&#039;s say. Suddenly, the chances of that thing happening are increased by 20%. How is that fraction written? Would you multiply 1/128 by 6/5 (yielding 3/320), or would you take 128, multiply it by 4/5, and then invert it (1/102)?This isn&#039;t for homework, I&#039;m merely curious.Thank you

Mateo Carson · Accepted Answer

Multiplying by   6      /    5  =  1.2 is the correct approach. This increases a value by   20  %. Multiplying by   4      /    5 decreases a value by   20  %, but inverting that is not the same as increasing by   20  %. It results in multiplying by   5      /    4, which is an increase of   25  %. On top of that,   128  ⋅      4    5    =  102.4  , not   102

ddcon4r · Accepted Answer

The first approach is correct.Initial   p  =            1      128      , you need to increase   p by   20  %NoteSince   p  =            1      128      , i.e. in the form of a fraction, it is possible to obtain the correct result by manipulating its denominator only, but then you would need to divide the denominator by   1.2i.e. multiply it by             5      6

If the chance of an event was 1 <mrow class="MJX-TeXAtom-ORD"> / </mrow> 128 and

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