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Ayaan Barr

Ayaan Barr

Answered question

2022-07-03

Let ( Ω , A ) be a measurable space, and let μ : A [ 0 , + ) be a monotone subadditive set function. Let moroever A 1 , A 2 , A be a sequence of measurable sets. It is easy to prove that μ ( A n ) 0 μ ( A n c ) μ ( Ω ). On the contrary, I am not able neither to prove the opposite implication, namely μ ( A n ) μ ( Ω ) μ ( A n c ) 0, nor to find an example violating it. Can someone find either one or the other?

Answer & Explanation

Sophia Mcdowell

Sophia Mcdowell

Beginner2022-07-04Added 14 answers

It's not true that μ ( A n ) μ ( Ω ) μ ( A n c ) 0. Consider R endowed with the Lebesgue σ-algebra. Let A n = [ 0 , n ]. Then μ ( A n ) = n + = μ ( R ), but μ ( A n c ) = + for all n.

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