How can I find x, y values for ( 1 + i ) x − 2 i 3 + i + ( 2 − 3 i ) y + i 3 − i = iI believe the format I need in order to solve this problem should be such that the real parts and imaginary parts are separated, { R e a l } + { I m a g i n a r y } i = i Then I can equate the real and imaginary parts of the equation and solve for x and y. I tried to multiply by the conjugate so that I would get a real number at the denominator. Rearranged: x + i ( x − 2 ) 3 + i + 2 y + i ( − 3 y + 1 ) 3 − i = iMultiplied by conjugate: x ( 3 − i ) + i ( x − 2 ) ( 3 − i ) 10 + 2 y ( 3 + i ) + i ( − 3 y + 1 ) ( 3 + i ) 10 = iAnd at this step I started to feel as if I made a mistake because I weren't sure how to proceed. Would someone let me know if my approach was correct and show me how to do this?

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How can I find x, y values for             (      1      +      i      )      x      −      2      i              3      +      i        +            (      2      −      3      i      )      y      +      i              3      −      i        =  iI believe the format I need in order to solve this problem should be such that the real parts and imaginary parts are separated,   {      R    e    a    l    }  +  {      I    m    a    g    i    n    a    r    y    }  i  =  i Then I can equate the real and imaginary parts of the equation and solve for x and y. I tried to multiply by the conjugate so that I would get a real number at the denominator. Rearranged:            x      +      i      (      x      −      2      )              3      +      i        +            2      y      +      i      (      −      3      y      +      1      )              3      −      i        =  iMultiplied by conjugate:            x      (      3      −      i      )      +      i      (      x      −      2      )      (      3      −      i      )        10    +            2      y      (      3      +      i      )      +      i      (      −      3      y      +      1      )      (      3      +      i      )        10    =  iAnd at this step I started to feel as if I made a mistake because I weren&#039;t sure how to proceed. Would someone let me know if my approach was correct and show me how to do this?

toriannucz · Accepted Answer

x      (      3      −      i      )      +      i      (      x      −      2      )      (      3      −      i      )        10    +            2      y      (      3      +      i      )      +      i      (      −      3      y      +      1      )      (      3      +      i      )        10    =  i            3      x      −      i      x      +      3      i      x      +      x      −      6      i      −      2      +      6      y      +      2      i      y      −      9      i      y      +      3      y      +      3      i      −      1        10    =  i            4      x      +      9      y      −      3        10    +            i      (      2      x      −      7      y      −      3      )        10    =  0  +  i            4      x      +      9      y      −      3        10    =  0         a    n    d                 (      2      x      −      7      y      −      3      )        10    =  1solve simultaneously to obtain values for x and y

How can I find x, y values for ( 1 + i ) x &#x221

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