Let E be a normed <mrow class="MJX-TeXAtom-ORD"> <mi mathvariant="double-struck">R

Wronsonia8g

Wronsonia8g

Answered question

2022-07-05

Let E be a normed R -vector space, ( X t ) t 0 be an E-valued càdlàg Lévy process on a filtered probability space ( Ω , A , ( F t ) t 0 , P ), B B ( E ) with 0 B ¯ and
N t ( ω ) := | { s ( 0 , t ] : Δ X s ( ω ) B } | = s [ 0 , t ] Δ X s ( ω ) 1 B ( Δ X s ( ω ) )
for ω Ω and t 0.

How do we see that t N t ( ω ) is càdlàg?

Answer & Explanation

Alexzander Bowman

Alexzander Bowman

Beginner2022-07-06Added 19 answers

In order for N to be cadlag, it should be assumed that X has finite jump activity in B, i.e. ν ( B ) < , where ν is the Lévy measure of X (otherwise, it blows up to infinity immediately). And in such case, this is rather straightforward: with probability 1, the number of jumps in B is locally finite, and N t = n 1 1 [ τ n , ) ( t ), where τ n is the time of nth jump in B; this is clearly cadlag.

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