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Crystal Wheeler

Crystal Wheeler

Answered question

2022-07-06

I've F ( t ) = 0 e t x 3 1 + x 4 d x and I have to see that it is well defined on the interval ( 0 , ).
For that, I have defined f ( x , t ) = e t x 3 1 + x 4 , x , t ( 0 , ) so I have to see if f is integrable in ( 0 , ).
We know that f is integrable on ( 0 , ) | f | d μ <
f ( x , t ) = | e t x 3 1 + x 4 | = e t x 3 1 + x 4 e t x 3
But hoe can I bound this? I have to bound it with an integrable function... but I don't know how to calculate the integral of e t x 3 ... Is there any other easier way to bound that? Or how can I solve my problem?

Answer & Explanation

Immanuel Glenn

Immanuel Glenn

Beginner2022-07-07Added 12 answers

Hint: 0 1 e t x 3 d x 0 1 1 d x and 1 e t x 3 d x 1 e t x d x
To prove continuity of F it is enough to prove continuity on (r,∞) for each r>0. When t > r we have | f ( x , t ) | max { 1 0 < x < 1 , e r x }. Now apply DCT to prove sequential continuity of F.

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