Finding all possible pairs of positive integer valuesThe ratio of the sum of two positive integers to their difference is 7:5. If the the sum of the two numbers is at most 25, find all possible values for the pair of numbers.Let m be the first positive integer.Then m 6 is the second positive integer.This gives m = 21.4, but now I'm stuck?

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Finding all possible pairs of positive integer valuesThe ratio of the sum of two positive integers to their difference is 7:5. If the the sum of the two numbers is at most 25, find all possible values for the pair of numbers.Let   m be the first positive integer.Then       m    6   is the second positive integer.This gives   m  =  21.4, but now I&#039;m stuck?

amanhantmk · Accepted Answer

Assuming    x  ≥  y We have it that  5  (  x  +  y  )  =  7  (  x  −  y  )and that   x  +  y  ≤  25Continuing with the above equality we get  5  x  +  5  y  =  7  x  −  7  y  2  x  =  12  y  x  =  6  yhence the solutions are   (  1  ,  6  )  ,  (  2  ,  12  )  ,  (  3  ,  18  )

Finding all possible pairs of positive integer values The ratio of the sum of two positive integers

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