Fraction involving SurdsFraction involving Surds. Can anyone please show me the working out? ( 6 − 1 ) 3 + ( 6 + 2 ) 2 3 I did this and it was incorrect: 2 3 ( 6 − 1 ) + 3 ( 6 + 2 ) 3 × 2 3 2 s q r t 3 ( 6 − 1 ) 3 + s q r t 3 ( 6 + 2 ) 2 3

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Fraction involving SurdsFraction involving Surds. Can anyone please show me the working out?            (              6            −      1      )              3        +            (              6            +      2      )              2              3            I did this and it was incorrect:  2      3    (      6    −  1  )  +                    3            (              6            +      2      )                      3            ×      2              3                        2      s      q      r      t              3            (              6            −      1      )              3        +            s      q      r      t      3      (              6            +      2      )              2              3

talhekh · Accepted Answer

(                          6                        −            1            )                                3                          +                              (                          6                        +            2            )                                2                          3                                                  =                              2            (                          6                        −            1            )                                2                          3                                      +                              (                          6                        +            2            )                                2                          3                                              put the fractions over a common denominator                                  =                              2            (                          6                        −            1            )            +            (                          6                        +            2            )                                2                          3                                              add the numerators                                  =                              2                          6                        −            2            +                          6                        +            2                                2                          3                                              use the distributive law to get rid of parentheses                                  =                              3                          6                                            2                          3                                              simple algebra                                  =                              3                          2              ⋅              3                                            2                          3                                              setup to get rid of                   3                                          =                              3                          2                                      3                                            2                          3                                              use                   x          y                =                  x                          y                                          =                              3                          2                                2                        and its gone

Fraction involving Surds Fraction involving Surds. Can anyone please show me the working out?

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